{1 2} --------- {1 2}
: :
{1 2} --------- {1 2 3}
denis_berthier wrote:
- Code: Select all
{1 2} --------- {1 2}
: :
{1 2} --------- {1 2 3}
(all 4 cells in exactly two rows, two columns and two blocks)
and by the conclusion that 3 can be asserted in the rightmost bottom cell.
Suppose we add UR1 to T.
Suppose this patterns appears at some point in the resolution process of a puzzle P but, for any reason, rule UR1 is not applied immediately (e.g. because you haven't seen it). If any candidate in any of the other 3 cells is eliminated by any other rule in T, then, using ECP and NS, these 3 cells are reduced to one candidate and the 4th cell is reduced to {1 3} or {2 3}.
What remains is the mere pattern of bivalue cell, for which there can exist no resolution rule able to eliminate 1 or 2.
q.e.d.
ronk wrote:When none of the UR cells is a given, missing UR digits may be freely "reinvented."
q.e.d.
Denis wrote:As I'm not interested by uniqueness, that's all I'll say about it.
Myth Jellies wrote:The simplest refutation is that UR type 1 is not completely defined by that pattern, therefore your proof is invalid.
Myth Jellies wrote:Another confluence observation concerns your non-degenerate naked triple. Let us choose T to be your non-degenerate naked triple along with the singles. Seems to me that one could come up with a puzzle where the naked triple could knock out a candidate, but the pattern gets partially whacked by a single that gets applied first, and you can't use the triple deduction any more.
denis_berthier wrote:The T you are defining here clearly doesn't have the confluence property: you must add Pairs to obtain it.
ronk wrote:denis_berthier wrote:The T you are defining here clearly doesn't have the confluence property: you must add Pairs to obtain it.
True, unless the triple subsumes the degenerate case of a naked pair and a single.
denis_berthier wrote:ronk wrote:When none of the UR cells is a given, missing UR digits may be freely "reinvented."
q.e.d.
Where do you see that candidates can be "reinvented" in my framework?
And anyway, which candidates would you reinvent when you haven't seen the UR and you are left with only a bivalue cell?
ronk wrote:denis_berthier wrote:ronk wrote:When none of the UR cells is a given, missing UR digits may be freely "reinvented."
q.e.d.
Where do you see that candidates can be "reinvented" in my framework?
And anyway, which candidates would you reinvent when you haven't seen the UR and you are left with only a bivalue cell?
Although it may not answer your questions directly, I defer to the discussion in progresshere.
denis_berthier wrote:Myth Jellies wrote:The simplest refutation is that UR type 1 is not completely defined by that pattern, therefore your proof is invalid.
This is typical of your flawed reasoning: concluding something is false, just by negating the definitions used to prove it
denis_berthier wrote:(but, of course, not proposing any other definition, so that no discussion is possible).
denis_berthier wrote:BTW, I found the definition I used here in Andrew Stuart's book. Is it all scrap
denis_berthier wrote:(to use your elegant vocabulary)?
denis_berthier wrote:Myth Jellies wrote:Another confluence observation concerns your non-degenerate naked triple. Let us choose T to be your non-degenerate naked triple along with the singles. Seems to me that one could come up with a puzzle where the naked triple could knock out a candidate, but the pattern gets partially whacked by a single that gets applied first, and you can't use the triple deduction any more.
"seems to you": very convincing purely logical proof.
denis_berthier wrote:Seems you also failed to understand this: you can't take any set of rules and claim it has the confluence property.
Myth Jellies wrote:denis_berthier wrote:Myth Jellies wrote:The simplest refutation is that UR type 1 is not completely defined by that pattern, therefore your proof is invalid.
This is typical of your flawed reasoning: concluding something is false, just by negating the definitions used to prove it
That was just the simplest refutation concluding the proof was invalid. If you don't believe that invalidates a proof, then that explains much.
Myth Jellies wrote:denis_berthier wrote:(but, of course, not proposing any other definition, so that no discussion is possible).
Perhaps if you would have kept the discussion in the thread I created for it instead of burying it in this one, you might have noticed that I came up with a potentially degenerate UR+1 pattern (which I also mentioned here).
Myth Jellies wrote:denis_berthier wrote:Seems you also failed to understand this: you can't take any set of rules and claim it has the confluence property.
I understand it perfectly--I'm pointing it out to you!
Myth Jellies wrote:I understand that I CAN'T take any set of YOUR rules and claim it has the confluence property
Myth Jellies wrote:I also understand that I CAN take any set of my potentially degenerate pattern based rules and claim it DOES possess the confluence property.
Do you understand yet?
ronk wrote:OFF TOPIC -- Hasn't Bill Richter left yet?
Oops, with decorum degenerating so rapidly here, for a minute there I thought I was on the Eureka! forum.
{1 2} --------- {1 2}
: :
{1 2} --------- {1 2 3}
~{3-9} --------- ~{3-9}
: :
~{3-9} --------- ~{4-9}
{1} --------- {2}
: :
{2} --------- {1 3}
with the added proviso that the "solved" cells here were not among the original givens.
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