
For completeness, click three times to see what I wrote:
The bottom line is 26135~4
The balance of the 10 cannot be 63 as I have used up the 6s in c23 (once 56 is inserted in r2c23).
If it is 25, I have
000000
056000
000500
500600
625100
26134~5
And moving onwards forces
000000
056000
003503
534612
62513~4
26134~5 with two 3s in r3 ERROR
The balance of the 10 is therefore 45iso
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